How do you write #2(cos300+isin300) in retangular form?

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Answer 1 · 2015-02-03T10:03:13

The answer is: $z=1-sqrt3i$ .

The rectangular form of a complex number is:

$z=a+ib$ ,

and we have a number written in trigonometric form, that is:

$z=rho(sintheta+icostheta)$ .

So the real part of the numer is $rhosintheta=2cos300°=2*1/2=1$ and the imaginary part is $2sin300°=2*(-sqrt3/2)=-sqrt3$ .

So:

$z=1-sqrt3i$ .