How do you write $3 [(cos (\frac{π}{10}) + i sin (\frac{π}{10})]$ $3[(cos(pi/10) + i sin (pi/10)]$ in rectangular form?

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How do you write $3 [(cos (\frac{π}{10}) + i sin (\frac{π}{10})]$ $3[(cos(pi/10) + i sin (pi/10)]$ in rectangular form?

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Answer 1 · 2016-02-12T05:22:12

(2.853, 0.9271) or, explicitly, 2.853 + i 0.9271,

Explanation:

In rectangular form of a complex number, with real part x and imaginary part y, we use the ordered pair (x, y) to represent the complex number x + i y. Converting to polar coordinates,, using $x = r cos (θ) and y = r sin (θ)$ $x = r cos(theta) and y = r sin(theta)$ ,, it becomes (r, $θ) = r (cos (θ) + i sin (θ)) . H e r e, r = 3 and θ = \frac{π}{10} = 18 d e g$ $theta) = r ( cos(theta) + i sin(theta)). Here, r = 3 and theta = pi/10 = 18 deg$

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How do you write $3 [(cos (\frac{π}{10}) + i sin (\frac{π}{10})]$ $3[(cos(pi/10) + i sin (pi/10)]$ in rectangular form?

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How do you write 3[(cos(π10)+isin(π10)]3[(cos(pi/10) + i sin (pi/10)] in rectangular form?

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How do you write $3 [(cos (\frac{π}{10}) + i sin (\frac{π}{10})]$ $3[(cos(pi/10) + i sin (pi/10)]$ in rectangular form?