How do you write a direct variation equation that relates x and y if y=-8 when x= 2, and how do you find y when x=32?

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How do you write a direct variation equation that relates x and y if y=-8 when x= 2, and how do you find y when x=32?

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Answer 1 · 2015-04-10T18:20:23

A direct variation equation is of the form
$y = m x$ $y = mx$ for some constant value $m$ $m$

We are told that $(x, y) = (2, - 8)$ $(x,y) = (2,-8)$ satisfies the required equation, so
$(- 8) = m (2)$ $(-8) = m(2)$
$\to m = (- 4)$ $rarr m= (-4)$
and the direct variation equation is
$y = (- 4) x$ $y = (-4)x$

When $x = 32$ $x=32$
$y = (- 4) (32) = (- 128)$ $y = (-4)(32) = (-128)$

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How do you write a direct variation equation that relates x and y if y=-8 when x= 2, and how do you find y when x=32?

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