How do you write an equation of $y = sin x$ $y=sinx$ with pi/2 units to the right and 3.5 units up?

Question

How do you write an equation of $y = sin x$ $y=sinx$ with pi/2 units to the right and 3.5 units up?

1 Answer

Impact of this question

9448 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-03T18:48:04

$y = sin (x - \frac{π}{2}) + \frac{7}{2}$ $y= sin(x-pi/2)+7/2$

Explanation:

Subtracting $\frac{π}{2}$ $pi/2$ from $x$ $x$ will move the graph $\frac{π}{2}$ $pi/2$ units to the right. Adding $\frac{π}{2}$ $pi/2$ to $x$ $x$ will move the graph $\frac{π}{2}$ $pi/2$ units to the left.

Adding a constant to $sin x$ $sinx$ will translate the graph up for positive value and down for a negative value.

So:

$y = sin x$ $y=sinx$ becomes $y = sin (x - \frac{π}{2}) + \frac{7}{2}$ $y= sin(x-pi/2)+7/2$

See graphs:

enter image source here

Science

Math

Humanities

... and beyond

How do you write an equation of $y = sin x$ $y=sinx$ with pi/2 units to the right and 3.5 units up?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write an equation of y=sinxy=sinx with pi/2 units to the right and 3.5 units up?

1 Answer

Explanation:

Related questions

Impact of this question

How do you write an equation of $y = sin x$ $y=sinx$ with pi/2 units to the right and 3.5 units up?