How do you write the complex number $-2-3i$ in polar form?

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Answer 1 · 2018-07-02T11:00:24

Polar form of $-2 -3i = (3.6056, 236.31^@)$

$z =a + i b = r (cos theta + i sin theta)$

$r = |sqrt(a^2 + b^2)| = sqrt (-2^2 + -3^2) = 3.6056$

$theta = tan^-1 (b/a) = tan ^-1 (-3/-2) = 236.31^@ " Point in III Quadrant"$

How do you write the complex number -2-3i-2-3i in polar form?