How do you write the complex number $3 + 3 i$ $3+3i$ in polar form?

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Answer 1 · 2017-02-14T14:30:59

$3 \sqrt{2} (cos \frac{π}{4} + i sin \frac{π}{4})$ $3 sqrt 2 (cos frac{pi}{4} + i sin frac{pi}{4})$

$x = r cos t, y = r sin t$ $x = r cos t, y = r sin t$

$3 = r cos t, 3 = r sin t$ $3 = r cos t, 3 = r sin t$

$3^{2} + 3^{2} = r^{2} = 9 + 9 = 18$ $3^2 + 3^2 = r^2 = 9 + 9 = 18$

$r = \sqrt{18} = 3 \sqrt{2}$ $r = sqrt 18 = 3 sqrt 2$

$tan t = \frac{3}{3} = 1$ $tan t = 3/3 = 1$

$t = \frac{π}{4}$ $t = pi/4$

How do you write the complex number 3+3i3+3i in polar form?