How do you write the complex number in trigonometric form $3 i$ $3i$ ?

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How do you write the complex number in trigonometric form $3 i$ $3i$ ?

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Answer 1 · 2016-10-30T13:48:15

the trigonometric form is $3 (cos (\frac{π}{2}) + i sin (\frac{π}{2}))$ $3(cos(pi/2)+isin(pi/2))$

Explanation:

This complex number has only the imaginary part:
so, $cos θ = 0$ $cos theta=0$ and $sin θ = 1$ $sintheta=1$
So $θ = \frac{π}{2}$ $theta=pi/2$
So the trigonometric form is $3 (cos (\frac{π}{2}) + i sin (\frac{π}{2}))$ $3(cos(pi/2)+isin(pi/2))$
and you can also write it as $3 e^{i \frac{π}{2}}$ $3e^(ipi/2)$

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How do you write the complex number in trigonometric form $3 i$ $3i$ ?

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Science

Math

Humanities

... and beyond

How do you write the complex number in trigonometric form 3i3i?

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Explanation:

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How do you write the complex number in trigonometric form $3 i$ $3i$ ?