How do you write the complex number in trigonometric form 4-4sqrt3i4−4√3i?
1 Answer
Mar 18, 2017
Explanation:
(x,y)tor(costheta+isintheta)(x,y)→r(cosθ+isinθ)
color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(r=sqrt(x^2+y^2))color(white)(2/2)|)))
"and " color(red)(bar(ul(|color(white)(2/2)color(black)(theta=tan^-1(y/x))color(white)(2/2)|)))
"here "x=4" and " y=-4sqrt3
rArrr=sqrt((4)^2+(-4sqrt3)^2)=sqrt64=8
"now " 4-4sqrt3 is in the 2nd quadrant so we must ensure that
theta is in the 2nd quadrant.
rArrtan^-1((4sqrt3)/4)=tan^-1(sqrt3)=pi/3
rArrtheta=(pi-pi/3)=(2pi)/3larrcolor(red)" in 2nd quadrant"
rArr4-4sqrt3i=8[cos((2pi)/3)+isin((2pi)/3)]