How do you write the partial fraction decomposition of the rational expression (9x^2 + 1)/(x^2(x − 2)^2)9x2+1x2(x−2)2?
1 Answer
Explanation:
Given that we have squared linear factors in the denominator, the decomposition will take a form like:
(9x^2+1)/(x^2(x-2)^2) = A/x+B/x^2+C/(x-2)+D/(x-2)^29x2+1x2(x−2)2=Ax+Bx2+Cx−2+D(x−2)2
Multiplying both sides by
9x^2+1 = Ax(x-2)^2+B(x-2)^2+Cx^2(x-2)+Dx^29x2+1=Ax(x−2)2+B(x−2)2+Cx2(x−2)+Dx2
Putting
1 = 4B" "1=4B so" "B = 1/4 B=14
Putting
37 = 4D" "37=4D so" "D=37/4 D=374
Looking at the coefficient of
0 = 4A-4B = 4A-1" "0=4A−4B=4A−1 and henceA=1/4A=14
Looking at the coefficient of
0 = A+C" "0=A+C and henceC=-A=-1/4C=−A=−14
So:
(9x^2+1)/(x^2(x-2)^2) = 1/(4x)+1/(4x^2)-1/(4(x-2))+37/(4(x-2)^2)9x2+1x2(x−2)2=14x+14x2−14(x−2)+374(x−2)2