How do you write the trigonometric form in complex form $4(cos((3pi)/2)+isin((3pi)/2)))$ ?

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Answer 1 · 2017-01-06T06:31:38

The answer is $=-4i$

Let $z=4(cos((3pi)/2)+isin((3pi)/2))$

$cos((3pi)/2)=0$

$sin((3pi)/2)=-1$

Therefore,

$z=4(0-1*i)$

$z=-4i$

How do you write the trigonometric form in complex form 4(cos((3pi)/2)+isin((3pi)/2)))4(cos((3pi)/2)+isin((3pi)/2)))?