How do you write the trigonometric form into a complex number in standard form $10 (cos (\frac{2 π}{5}) + i sin (\frac{2 π}{5}))$ $10(cos((2pi)/5)+isin((2pi)/5))$ ?

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Answer 1 · 2017-10-22T15:09:34

$(3.090169938 + 9.510565165 i)$ $(3.090169938 + 9.510565165 i)$

$10 (cos (\frac{2 π}{5}) + i sin (\frac{2 π}{5}))$ $10(cos((2pi)/5)+ i sin((2pi)/5))$

$10 cos (\frac{2 π}{5}) = 3.090169938$ $10cos((2pi)/5)=3.090169938$

$10 (i sin (\frac{2 π}{5})) = 9.510565165 i$ $10(i sin((2pi)/5))=9.510565165 i$

$(3.090169938 + 9.510565165 i)$ $(3.090169938 + 9.510565165 i)$

How do you write the trigonometric form into a complex number in standard form 10(cos(2π5)+isin(2π5))10(cos((2pi)/5)+isin((2pi)/5))?