How do you write the trigonometric form into a complex number in standard form $3(cos120+isin120)$ ?

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Answer 1 · 2017-01-21T14:15:58

The answer is $=-3/2+i(3sqrt3)/2$

$cos120=-1/2$

$sin120=sqrt3/2$

Therefore,

$3(cos120+isin120)=3*(-1/2+isqrt3/2)$

$=-3/2+i(3sqrt3)/2$

How do you write the trigonometric form into a complex number in standard form 3(cos120+isin120)3(cos120+isin120)?