How do you write the trigonometric form into a complex number in standard form $3(cos(18^o 45')+isin(18^o 45')$ ?

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Answer 1 · 2018-07-08T02:04:20

$color(purple)("Complex number is " 2.8408 + 0.9643 i$

Trigonometric form to complex form.

![https://www.ck12.org/trigonometry/trigonometric-form-of-complex-numbers/lesson/Trigonometric-Form-of-Complex-Numbers-TRIG/](https://useruploads.socratic.org/Dm8MyneuTTW96l6EVZyM_complex.1)

$x = r cos theta = 3 * cos (18^@ 45') = 2.8408$

$y = r sin theta = 3 * sin (18^@ 45') = 0.9643$

$color(purple)("Complex number is " 2.8408 + 0.9643 i$

How do you write the trigonometric form into a complex number in standard form 3(cos(18^o 45')+isin(18^o 45')3(cos(18^o 45')+isin(18^o 45')?