Question

How do you write the trigonometric form into a complex number in standard form `6(cos(230^o 30')+isin(230^o 30')`?

Answer 1

`cos(230^o30')=-0.6361` in standard form is `-3.8166-4.6296i`

Explanation:

As `cos(230^o30')=-0.6361` and

`sin(230^o30')=-0.7716`

`6(cos(230^o30')+isin(230^o30'))`

= `6(-0.6361-i0.7716)`

= `-3.8166-4.6296i`