How do you write the trigonometric form into a complex number in standard form $6(cos(230^o 30')+isin(230^o 30')$ ?

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Answer 1 · 2016-10-26T10:24:56

$cos(230^o30')=-0.6361$ in standard form is $-3.8166-4.6296i$

As $cos(230^o30')=-0.6361$ and

$sin(230^o30')=-0.7716$

$6(cos(230^o30')+isin(230^o30'))$

= $6(-0.6361-i0.7716)$

= $-3.8166-4.6296i$

How do you write the trigonometric form into a complex number in standard form 6(cos(230^o 30')+isin(230^o 30')6(cos(230^o 30')+isin(230^o 30')?