How do you write the trigonometric form into a complex number in standard form $8 (cos (\frac{π}{2}) + i sin (\frac{π}{2}))$ $8(cos((pi)/2)+isin((pi)/2))$ ?

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Answer 1 · 2017-02-28T06:52:43

$8 (cos (\frac{π}{2}) + i sin (\frac{π}{2}))$ $8(cos((pi)/2)+isin((pi)/2))$ in standard form is $0 + 8 i$ $0+8i$ .

$8 (cos (\frac{π}{2}) + i sin (\frac{π}{2}))$ $8(cos((pi)/2)+isin((pi)/2))$

= $8 cos (\frac{π}{2}) + 8 i sin (\frac{π}{2})$ $8cos((pi)/2)+8isin((pi)/2)$

= $8 \times 0 + 8 i \times 1$ $8xx0+8ixx1$

= $0 + 8 i$ $0+8i$

which is the complex number in standard form.

How do you write the trigonometric form into a complex number in standard form 8(cos(π2)+isin(π2))8(cos((pi)/2)+isin((pi)/2))?