How do you write the trigonometric form into a complex number in standard form $9(cos58+isin58)$ ?

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Answer 1 · 2016-09-24T12:30:08

$9(cos58+isin58)=4.734+i7.632$

A complex number $r(costheta+isintheta)$ can be written into complex form as $a+ib$ ,

where $a=rcostheta$ and $b=rsintheta$

Hence $9(cos58+isin58)$

= $9cos58+i9sin58$

= $9xx0.526+i9xx0.848$

= $4.734+i7.632$

How do you write the trigonometric form into a complex number in standard form 9(cos58+isin58)9(cos58+isin58)?