Question

How do you write the trigonometric form of `-6`?

Answer 1

I found: `z=6[cos(pi)+isin(pi)]`

Explanation:

We can "see" this number (`z=-6`) on the Real axis on a complex plane:

We need the angle `theta` and the modulus (length) to define the characteristics of our number in trig form as:
`z="modulus"[cos(theta)+isin(theta)]`
observing our complex plane we see that:
modulus`=6`
`theta=pi=180^@`
so ve get:
`z=6[cos(pi)+isin(pi)]`