How do you write this equation in polar coordinates: #x^2 + y^2 = 2#? Precalculus Polar Equations of Conic Sections Writing Polar Equations for Conic Sections 1 Answer Alan P. Jun 13, 2016 #{(r,theta):r^2=2}# Explanation: #x^2+y^2=2# is a circle with radius (#r#) equal to #2# Note that the angle (#theta#) is not constrained by this equation (similar to the way #y# is not constrained by the linear equation #x=5#) Answer link Related questions How do you identify conic sections? What is the meaning of conic section? What is the standard equation of a circle? What is the standard equation of a parabola? What is the standard equation of a hyperbola? Which conic section has the polar equation #r=1/(1-cosq)#? Which conic section has the polar equation #r=2/(3-cosq)#? Which conic section has the polar equation #r=a sintheta#? How do you find a polar equation for the circle with rectangular equation #x^2+y^2=25#? What are the polar coordinates of #(x-1)^2-(y+5)^2=-24#? See all questions in Writing Polar Equations for Conic Sections Impact of this question 1471 views around the world You can reuse this answer Creative Commons License