Question

If chlorine gas has a volume of 465mL at 50°C ,what is the volume if the temperature decreases to 30°C?

Answer 1

`V_2=436mL`

Explanation:

To answer this question, we will need to assume the following:

1. Chlorine gas is behaving ideally, so we can use the ideal gas law: `PV=nRT`
2. During the process, the pressure is remaining constant.

Since we are heating the ballon, the number of mole is not changing and therefore, `n` is constant too.

Thus `V=underbrace((nR)/P)_(color(blue)("constant k"))T=>V/T=k=>(V_1)/(T_1)=(V_2)/(T_2)`

`=>V_2=(V_1)/(T_1)xxT_2=(465mL)/(323cancel(K))xx303cancel(K)=436mL`

Therefore, chlorine will occupy a volume of `436mL` at `30^@C`.