If the cost of a telephone conversation varies directly as the length of the time of conversation, and if the cost of six minutes is $0.90, what would be the cost for a nine-minute call?

Question

3669 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-05T09:48:13

Cost for a #9# minute call is #$1.35#

Let length of time be #t# minutes and cost is #$c#, then,

#c prop t or c = kt or k = c/t; k # is variation constant.

# t= 6 , c =$0.90:. k = 0.90/6=0.15 # , therefore, variation

equation is #c = 0.15 t ; t= 9 , c= ? c =0.15*9=$1.35#

Cost for a #9# minute call is #$1.35# [Ans]

Answer 2 · 2018-08-05T14:06:29

Cost = #$1.35#

As the cost is proportional to the time you can set up a direct proportion using equivalent fractions:

#6/0.90 =9/x" "(larr "minutes")/(larr "cost")#

#x = (9xx0.90)/6#

#=1.35#