Is $2 y - 5 x = 0$ $2y-5x=0$ a direct variation equation and if so what is the constant?

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Answer 1 · 2016-03-05T06:04:09

Yes. $k = \frac{5}{2}$ $k = 5/2$

When we say that a variable $y$ $y$ directly varies with $x$ $x$ , we express it in the form

$y = k x$ $y = kx$

Given $2 y - 5 x = 0$ $2y - 5x = 0$ , we have

$\Rightarrow 2 y = 5 x$ $=> 2y = 5x$

$\Rightarrow y = \frac{5}{2} x$ $=> y = 5/2x$

We were able to able express $y$ $y$ in terms of $x$ $x$ and we have $k = \frac{5}{2}$ $k = 5/2$

Is 2y−5x=02y-5x=0 a direct variation equation and if so what is the constant?