The area of a rectangle is #20x^2-27x-8#. The length is #4x+1#. What is the width?

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Answer 1 · 2017-03-13T07:38:40

The width is #=(5x-8)#

The area of a rectangle is

#A=L * W#

#A=20x^2-27x-8#

#L=4x+1#

#W=A/L=(20x^2-27x-8)/(4x+1)#

We perform a long division

#color(white)(aaaa)##20x^2-27x-8##color(white)(aaaa)##|##4x+1#

#color(white)(aaaa)##20x^2+5x##color(white)(aaaaaaaaa)##|##5x-8#

#color(white)(aaaaaaa)##0-32x-8#

#color(white)(aaaaaaaaa)##-32x-8#

#color(white)(aaaaaaaaaaa)##-0-0#

Therefore,

#W=5x-8#