What are the absolute extrema of $y = {cos}^{2} x - {sin}^{2} x$ $y=cos^2 x - sin^2 x$ on the interval [-2,2]?

Question

What are the absolute extrema of $y = {cos}^{2} x - {sin}^{2} x$ $y=cos^2 x - sin^2 x$ on the interval [-2,2]?

1 Answer

Impact of this question

2444 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-20T19:12:31

${cos}^{2} x - {sin}^{2} x = cos (2 x)$ $cos^2x-sin^2x = cos(2x)$ which has a maximum value of $1$ $1$ (at $x = 0$ $x=0$ ) and a minimum value of $- 1$ $-1$ (at $2 x = π$ $2x = pi$ so $x = \frac{π}{2}$ $x = pi/2$ )

Science

Math

Humanities

... and beyond

What are the absolute extrema of $y = {cos}^{2} x - {sin}^{2} x$ $y=cos^2 x - sin^2 x$ on the interval [-2,2]?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What are the absolute extrema of y=cos2x−sin2xy=cos^2 x - sin^2 x on the interval [-2,2]?

1 Answer

Related questions

Impact of this question

What are the absolute extrema of $y = {cos}^{2} x - {sin}^{2} x$ $y=cos^2 x - sin^2 x$ on the interval [-2,2]?