What are the components of the vector between the origin and the polar coordinate $(-6, (7pi)/8)$ ?

Question

1370 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-27T05:22:48

$x = -6 * cos ((7pi)/8) = 5.5433$

$y = -6 * sin ((7pi)/8) = - 2.2961$

Conversion of polar to rectangular coordinates.

$x = r cos theta, y = r sin theta$

$x = -6 * cos ((7pi)/8) = 5.5433$

$y = -6 * sin ((7pi)/8) = - 2.2961$

$tan theta = y / x = - 2.2961 / 5.5432 = tan ((7pi)/8) = -0.4142$

What are the components of the vector between the origin and the polar coordinate (-6, (7pi)/8)(-6, (7pi)/8)?