What are the components of the vector between the origin and the polar coordinate (2, (-pi)/6)?

1 Answer
Mar 5, 2016

=sqrt3hati-hatj

Explanation:

if (r,theta) be the polar coordinate of position vector veca with respect to the origin then then veca= rcosthetahati+rsinthetahatj
Hence for the coordinate (2,-pi/6) the vector becomes

veca=2cos(-pi/6)hati+2sin(-pi/6)hatj=sqrt3hati-hatj