What are the components of the vector between the origin and the polar coordinate (5, (13pi)/12)?

1 Answer
Apr 7, 2016

(-5 cos (pi/12), -5 sin(pi/12)) = (-4.83, -1.39), nearly.

Explanation:

The components of the radial vector to (r, theta) are (x, y) = (r cos theta, r sin theta).

Here, r = 5 and theta = - 13pi/12=pi+pi/12 (in the third quadrant)..

cos (pi+pi/12)=-cos(pi/12) and sin (pi+pi/12)=-sin(pi/12).

So, the components (x, y) =(-5 cos (pi/12), -5 sin(pi/12)) = (-4.83, -1.39), nearly.