Question

What are the components of the vector between the origin and the polar coordinate `(-9, (5pi)/4)`?

Answer 1

The x-component and the y-component are both `\frac{9sqrt2}2`

Explanation:

To find the components of a vector given the polar coordinate creating the vector, you do the following:

`(r, \theta) =>(rcos(\theta), rsin(\theta))`

In this case:

`(-9, (5pi)/4) => (-9cos((5pi)/4), -9sin((5pi)/4))`
`=> (\frac{9sqrt2}2, \frac{9sqrt2}2)`

So the x-component and the y-component are both `\frac{9sqrt2}2`