What are the components of the vector between the origin and the polar coordinate $(- 8, \frac{5 π}{3})$ $(-8, (5pi)/3)$ ?

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What are the components of the vector between the origin and the polar coordinate $(- 8, \frac{5 π}{3})$ $(-8, (5pi)/3)$ ?

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Answer 1 · 2016-02-06T15:18:43

$- 4 i + 4 \sqrt{3} j$ $-4i +4sqrt3 j$

Explanation:

In cartesian coordinates $x = r cos θ$ $x= rcos theta$ . In this case it would be $x = - 8 cos (\frac{5 π}{3}) = - 8 cos (- \frac{π}{3}) = - 4$ $x=-8 cos ((5pi)/3)= -8cos (-pi/3)= -4$ and $y = r sin θ = - 8 sin (\frac{5 π}{3}) = - 8 sin (- \frac{π}{3}) = 4 \sqrt{3}$ $y= r sin theta= -8 sin((5pi)/3)= -8 sin (-pi/3)= 4sqrt3$ . The point would lie in 2nd quadrant.

Its vector form would be $- 4 i + 4 \sqrt{3} j$ $-4i +4sqrt3 j$

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What are the components of the vector between the origin and the polar coordinate $(- 8, \frac{5 π}{3})$ $(-8, (5pi)/3)$ ?

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Explanation:

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What are the components of the vector between the origin and the polar coordinate (−8,5π3)(-8, (5pi)/3)?

1 Answer

Explanation:

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What are the components of the vector between the origin and the polar coordinate $(- 8, \frac{5 π}{3})$ $(-8, (5pi)/3)$ ?