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What are the extrema of $f (x) = 3 x^{2} + 12 x + 16$ $f(x) = 3x^2 + 12x + 16$ ?

1 Answer

Nov 10, 2015

$x = - 2$ $x=-2$ is a minimum.

Explanation:

$f'(x)=6x+12=0$

$x=-2$

$f''(-2)=6>0$ $=>$ local minimum

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