What are the local extrema, if any, of f (x) =x^2-2x+4f(x)=x2−2x+4? Calculus Graphing with the First Derivative Identifying Turning Points (Local Extrema) for a Function 1 Answer Jim H Feb 21, 2017 f(1) = 3f(1)=3 is a local minimum. Explanation: f'(x) = 2x-2 Critical number x=1. f'(x) < 0 for x < 1 and f'(x) > 0 for x > 1, so f(1) = 3 is a local minimum. Answer link Related questions How do you find the x coordinates of the turning points of the function? How do you find the turning points of a cubic function? How many turning points can a cubic function have? How do you find the coordinates of the local extrema of the function? How do you find the local extrema of a function? How many local extrema can a cubic function have? How do I find the maximum and minimum values of the function f(x) = x - 2 sin (x) on the... If f(x)=(x^2+36)/(2x), 1 <=x<=12, at what point is f(x) at a minimum? How do you find the maximum of f(x) = 2sin(x^2)? How do you find a local minimum of a graph using the first derivative? See all questions in Identifying Turning Points (Local Extrema) for a Function Impact of this question 1177 views around the world You can reuse this answer Creative Commons License