What are the local extrema of $f(x)= e^(x^2)-x^2e^x$ ?

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Answer 1 · 2017-10-11T08:44:00

Let's see.

Let the function be $y$ .

$:.y=f(x)=e^(x^2)-x^2e^x$ .

Now find the $dy/dx$ and the $(d^2y)/dx^2$ .

Now follow some steps given in the following URL $rarr$

Hope it Helps:)

What are the local extrema of f(x)= e^(x^2)-x^2e^xf(x)= e^(x^2)-x^2e^x?