What is $11^{2} - 6 \cdot 11 + 5 \cdot 11$ $11^2 - 6 * 11 + 5 * 11$ ?

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Answer 1 · 2016-04-03T21:15:09

$11^{2} - 6 \cdot 11 + 5 \cdot 11 = 110$ $11^2−6⋅11+5⋅11 = 110$

$11^{2} = 121$ $11^2 = 121$

$6 \cdot 11 = 66$ $6⋅11 = 66$

$5 \cdot 11 = 55$ $5⋅11 = 55$

$121 - 66 = 55$ $121 − 66 = 55$

$55 + 55 = 110$ $55 + 55 = 110$

Answer 2 · 2016-06-14T23:44:17

We can immediately pull out a factor of $11$ $11$ :

$11^{2} - 6 \cdot 11 + 5 \cdot 11 = 11 (11 - 6 + 5)$ $11^2-6*11+5*11=11(11-6+5)$

Since $11 - 6 + 5 = 10$ $11-6+5=10$ :

$= 11 (10) = 110$ $=11(10)=110$

What is 112−6⋅11+5⋅1111^2 - 6 * 11 + 5 * 11?