What is $[(7-5)^5 -: 8]-4$ ?

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Answer 1 · 2016-04-03T16:35:43

$0$

Solve the brackets first.

$7 - 5 = 2$

Now you have

$(2^5/8)-4$ .

In fact, you don't even need to work out $2^5$ if you know that $8 = 2^3$ .

$2^5/2^3 = 2^(5-3) = 2^2 = 4$

And, obviously

$4 - 4 = 0$

What is [(7-5)^5 -: 8]-4[(7-5)^5 -: 8]-4?