Question

What is the arclength of `f(x)=sqrt(4-x^2)` in the interval `[-2,2]`?

Answer 1

The arc length is `2pi` units.

Explanation:

This is a semi circle of radius `2`. We simply find the perimeter of the full circle of radius `2` and divide it by `2` to get our arc length.

`P = 2(2)pi = 4pi`

`P/2 = (4pi)/2 = 2pi`

Therefore the arc length is `2pi` units.

Hopefully this helps!