What is the area of a rectangle that has a length of $5 x + 3$ $5x+3$ and width of $2 x - 3$ $2x-3$ ?

Question

23179 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-27T03:46:04

Area of the rectangle is $10 x^{2} - 9 x - 9$ $10x^2-9x-9$

Area of rectangle is the product of its length and width / breadth.

As length of given rectangle is $5 x + 3$ $5x+3$ and its width is $2 x - 3$ $2x-3$ ,

is area is $(5 x + 3) (2 x - 3)$ $(5x+3)(2x-3)$

= $5 x (2 x - 3) + 3 (2 x - 3)$ $5x(2x-3)+3(2x-3)$

= $10 x^{2} - 15 x + 6 x - 9$ $10x^2-15x+6x-9$

= $10 x^{2} - 9 x - 9$ $10x^2-9x-9$

What is the area of a rectangle that has a length of 5x+35x+35x+3 and width of 2x-32x−32x-3?