What is the area of a regular hexagon with side length of 8 m? Round your answer to the nearest tenth.

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Answer 1 · 2018-04-06T12:33:44

Area of the regular hexagon is #166.3# square meter.

A regular hexagon is comprised of six equilateral triangles.

Area of an equilateral triangle is #sqrt3/4*s^2# . Therefore,

area of a regular hexagon is #6*sqrt3/4*s^2 = 3sqrt3*s^2/2#

where #s=8# m is the length of a side of the regular hexagon.

Area of the regular hexagon is #A_h=(3*sqrt3*8^2)/2#

#=96*sqrt3 ~~ 166.3# square meter. [Ans]