What is the phase shift, vertical displacement with respect to $y = cos x$ $y=cosx$ for the graph $y = cos (x - \frac{5 π}{6}) + 16$ $y=cos(x-(5pi)/6)+16$ ?

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Answer 1 · 2017-05-18T18:59:24

Phase shift: $5 \frac{π}{6}$ $5pi/6$
Vertical displacement: $16$ $16$

The equation is in the form:

$y = A cos (b x - c) + d$ $y=Acos(bx-c)+d$

Where in this case , $A = B = 1$ $A=B=1$ , $C = 5 \frac{π}{6}$ $C=5pi/6$ , and $D = 16$ $D=16$

$C$ $C$ is defined as the phase shift. So the phase shift is $5 \frac{π}{6}$ $5pi/6$

$D$ $D$ is defined as the vertical displacement. So the vertical displacement is $16$ $16$

What is the phase shift, vertical displacement with respect to y=cosxy=cosxy=cosx for the graph y=cos(x-(5pi)/6)+16y=cos(x−5π6)+16y=cos(x-(5pi)/6)+16?