What is the phase shift, vertical displacement with respect to $y = sin x$ $y=sinx$ for the graph $y = sin (x - 50^{\circ}) + 3$ $y=sin(x-50^circ)+3$ ?

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What is the phase shift, vertical displacement with respect to $y = sin x$ $y=sinx$ for the graph $y = sin (x - 50^{\circ}) + 3$ $y=sin(x-50^circ)+3$ ?

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Answer 1 · 2017-01-11T19:00:58

$phase shift = + 50^{\circ}, vertical shift = + 3$ $"phase shift " =+50^@,"vertical shift" =+3$

Explanation:

The standard form of the $sine function$ $color(blue)"sine function"$ is.

$color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))$

$"where amplitude " =|a|," period " =360^@/b$

$"phase shift " =-c/b" and vertical displacement " =d$

$" here " a =1,b=1,c=-50^@" and " d=+3$

$rArr"phase shift " =-(-50^@)/1=+50^@rarr" shift right"$

$"and vertical displacement " =+3uarr$

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What is the phase shift, vertical displacement with respect to $y = sin x$ $y=sinx$ for the graph $y = sin (x - 50^{\circ}) + 3$ $y=sin(x-50^circ)+3$ ?

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Explanation:

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What is the phase shift, vertical displacement with respect to y=sinxy=sinxy=sinx for the graph y=sin(x-50^circ)+3y=sin(x−50∘)+3y=sin(x-50^circ)+3?

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Explanation:

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What is the phase shift, vertical displacement with respect to $y = sin x$ $y=sinx$ for the graph $y = sin (x - 50^{\circ}) + 3$ $y=sin(x-50^circ)+3$ ?