What is the trigonometric form of $13 e^{\frac{π}{12} i}$ $13 e^( ( pi)/12 i )$ ?

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What is the trigonometric form of $13 e^{\frac{π}{12} i}$ $13 e^( ( pi)/12 i )$ ?

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Answer 1 · 2016-03-18T15:18:32

$13 e^{\frac{π}{12} i} = 13 (cos (\frac{π}{12}) + i sin (\frac{π}{12}))$ $13e^(pi/12i)=13(cos(pi/12)+isin(pi/12))$

Explanation:

Euler's identity is a special case of Euler's formula from complex analysis, which states that for any real number x,
$e^{i x} = cos x + i sin x$ $e^{ix} = cos x + isin x$

$13 e^{\frac{π}{12} i} = 13 (cos (\frac{π}{12}) + i sin (\frac{π}{12}))$ $13e^(pi/12i)=13(cos(pi/12)+isin(pi/12))$

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What is the trigonometric form of $13 e^{\frac{π}{12} i}$ $13 e^( ( pi)/12 i )$ ?

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What is the trigonometric form of $13 e^{\frac{π}{12} i}$ $13 e^( ( pi)/12 i )$ ?