What is the trigonometric form of $15 e^{\frac{5 π}{12} i}$ $15 e^( ( 5 pi)/12 i )$ ?

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Answer 1 · 2016-06-12T11:36:46

It is $15 (cos (\frac{5 π}{12}) + i sin (\frac{5 π}{12}))$ $15(cos((5pi)/12)+isin((5pi)/12))$ .

The exponential and trigonometric functions are connected by the relationship

$e^{i x} = cos (x) + i sin (x)$ $e^(ix)=cos(x)+isin(x)$ .

For you the conversion is

$15 e^{i \frac{5 π}{12}} = 15 (cos (\frac{5 π}{12}) + i sin (\frac{5 π}{12}))$ $15e^(i(5pi)/12)=15(cos((5pi)/12)+isin((5pi)/12))$

What is the trigonometric form of 15e5π12i 15 e^( ( 5 pi)/12 i ) ?