What is the trigonometric form of $15 e^{\frac{π}{12} i}$ $15 e^( ( pi)/12 i )$ ?

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Answer 1 · 2016-10-06T14:38:58

$15 e^{\frac{π}{12} i} = 15 (cos (\frac{π}{12}) + i sin (\frac{π}{12}))$ $15e^(pi/12i)=15(cos(pi/12)+isin(pi/12))$

Trigonometric form of $r e^{i θ} = r (cos θ + i sin θ)$ $re^(itheta)=r(costheta+isintheta)$

Hence $15 e^{\frac{π}{12} i} = 15 (cos (\frac{π}{12}) + i sin (\frac{π}{12}))$ $15e^(pi/12i)=15(cos(pi/12)+isin(pi/12))$

What is the trigonometric form of 15eπ12i 15 e^( ( pi)/12 i ) ?