What is the trigonometric form of 2 e^( ( 7 pi)/12 i ) ?
1 Answer
Jan 23, 2016
2[ cos((7pi)/12) + isin((7pi)/12) ]
Explanation:
Euler's theorem states :
e^(itheta) = costheta + isintheta
rArr 2e^((7pi)/12 i= 2 [ cos((7pi)/12) + isin((7pi)/12) ]