What is the trigonometric form of $3 e^{\frac{π}{12} i}$ $3 e^( ( pi)/12 i )$ ?

Question

What is the trigonometric form of $3 e^{\frac{π}{12} i}$ $3 e^( ( pi)/12 i )$ ?

1 Answer

Impact of this question

1509 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-06T16:22:56

I found: $3 (cos (\frac{π}{12}) + i sin (\frac{π}{12}))$ $3(cos(pi/12)+isin(pi/12))$

Explanation:

You can change it as:
$ρ e^{i θ} = ρ (cos (θ) + i sin (θ))$ $rhoe^(itheta)=rho(cos(theta)+isin(theta))$
In your case:
$3 e^{\frac{π}{12} i} = 3 (cos (\frac{π}{12}) + i sin (\frac{π}{12}))$ $3e^(pi/12i)=3(cos(pi/12)+isin(pi/12))$

Science

Math

Humanities

... and beyond

What is the trigonometric form of $3 e^{\frac{π}{12} i}$ $3 e^( ( pi)/12 i )$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the trigonometric form of 3eπ12i 3 e^( ( pi)/12 i ) ?

1 Answer

Explanation:

Related questions

Impact of this question

What is the trigonometric form of $3 e^{\frac{π}{12} i}$ $3 e^( ( pi)/12 i )$ ?