What is the trigonometric form of 7 e^( ( 5 pi)/12 i ) ?

1 Answer
Aug 2, 2018

7 e^(((5pi)/12)i) = 7 * ( cos((5pi)/12) + i sin((5pi)/12))

Explanation:

Trigonometric form of e^ (ix), using Euler's Equation, is given by

e^ (ix) = cos x + i sin x

![www.songho.ca)

z = |z| e^(i x) = |z| * (cos theta + i sin theta)

7 e^(((5pi)/12)i) = 7 * ( cos((5pi)/12) + i sin((5pi)/12))