What is the trigonometric form of $8 e^{\frac{3 π}{2} i}$ $8 e^( (3pi)/2 i )$ ?

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Answer 1 · 2016-05-02T09:48:26

$8 e^{\frac{3 π}{2} i} = - 8 i$ $8e^((3pi)/2i)=-8i$

Trigonometric form of $8 e^{\frac{3 π}{2} i}$ $8e^((3pi)/2i)$ is

$8 (cos (\frac{3 π}{2}) + i sin (\frac{3 π}{2}))$ $8(cos((3pi)/2)+isin((3pi)/2))$

= $8 (0 + i \times (- 1) =$ $8(0+ixx(-1)=$ -8i#

What is the trigonometric form of 8e3π2i8 e^( (3pi)/2 i ) ?