What is the trigonometric form of $e^{\frac{5 π}{12} i}$ $e^( ( 5 pi)/12 i )$ ?

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What is the trigonometric form of $e^{\frac{5 π}{12} i}$ $e^( ( 5 pi)/12 i )$ ?

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Answer 1 · 2016-03-23T02:22:52

$e^{\frac{5 π}{12} i} = cos (\frac{5 π}{12}) + i sin (\frac{5 π}{12})$ $e^((5pi)/(12) i) = cos( (5pi)/12)+isin((5pi)/12)$

Explanation:

$e^{i θ} = cos θ + i sin θ$ $e^(itheta)=costheta+isintheta$
$θ = \frac{5 π}{12}$ $theta=(5pi)/12$
$e^{\frac{5 π}{12} i} = cos (\frac{5 π}{12}) + i sin (\frac{5 π}{12})$ $e^((5pi)/(12) i) = cos( (5pi)/12)+isin((5pi)/12)$

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What is the trigonometric form of $e^{\frac{5 π}{12} i}$ $e^( ( 5 pi)/12 i )$ ?

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What is the trigonometric form of e5π12i e^( ( 5 pi)/12 i ) ?

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What is the trigonometric form of $e^{\frac{5 π}{12} i}$ $e^( ( 5 pi)/12 i )$ ?