How do you find the slope and intercept to graph $y=1.25x+8$ ?

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Answer 1 · 2018-03-08T04:11:24

The slope is $1.25$ or $5/4$ . The $y$ -intercept is $(0, 8)$ .

The slope-intercept form is

$y=mx+b$

In an equation in slope-intercept form, the slope of the line will always be $m$ . The $y$ -intercept will always be $(0, b)$ .

graph{y=(5/4)x+8 [-21.21, 18.79, -6.2, 13.8]}

How do you find the slope and intercept to graph y=1.25x+8y=1.25x+8?