Find the equation of line whose making x intercept 3 and y intercept 8?

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Answer 1 · 2018-04-22T12:03:16

$y = - \frac{8}{3} x + 8$ $y = -8/3x + 8$

The gradient is

$m = \frac{rise}{run} = - \frac{8}{3}$ $m = "rise"/"run" = -8/3$

The $y$ $y$ -intercept, $c$ $c$ , is $8$ $8$ .

So

$y = m x + c$ $y = mx+c$

$y = - \frac{8}{3} x + 8$ $y = -8/3x + 8$

graph{(-8/3)x+8 [-5.19, 13.56, -0.73, 8.645]}