How do you solve #8(1+7m)+6=14#?

2 Answers
May 1, 2018

#m# = #0#

Explanation:

#8(1 + 7m) + 6 = 14#

First, distribute #8# to #(1 + 7m)#, per the distributive property. (Multiply 1 by 8 and 7m by 8). You should now have:

#8 + 56m + 6 = 14#

Combine like terms (8 and 6), and you should now have:

#14 + 56m = 14#

Re-order the terms where #56m# is first to help reduce confusion:

#56m + 14 = 14#

Subtract accordingly.

#56m = 0#

#m = 0#

Sources and for clarification:
https://www.symbolab.com/solver/equation-calculator/8%5Cleft(1%2B7m%5Cright)%2B6%20%3D%2014
https://www.wyzant.com/resources/lessons/math/algebra/calculators/equation?equation=8(1+%2B+7m)+%2B+6+%3D+14

#m = 0#

Explanation:

#8(1 + 7m) + 6 = 14#

Distribute the #8# by multiplying it into the parentheses.

#8 + 56m + 6 = 14#

Add the left side numbers without #m#.

#56m + 14 = 14#

Subtract both sides by #14#.

#56m + 14 - 14 = 14 - 14#

#56m = 0#

Divide both sides by #56#.

#(56m)/56 = 0/56#

#m = 0#