How do you graph using slope and intercept of #x+2y=5#?

1 Answer
Jun 2, 2018

#y=-0.5x+2.5#. Slope = #-0.5#, intercepts: #(0, 2.5)#, #(5, 0)#
graph{y=-0.5x+2.5 [-10, 10, -5, 5]}

Explanation:

#x+2y=5#
To get slope and intercept you need to rewrite the function so that y is to the left and expressed as a function of x, like this:
#2y=-x+5# (Subtract x on both sides of the equal sign)
#y=-1/2x+2 1/2# (divide both sides with 2)

Here the slope is #-1/2# (the constant in front of x).

We see that this graph intersects the y axis at #y= 2 1/2# when #x = 0#
and the x axis at #x=5# when y=0.

This gives the following graph:
graph{y=-0.5x+2.5 [-2.203, 6.57, -0.86, 3.523]}